Calcular la distancia entre dos ubicaciones geográficas

please shed some light on this situation

Right now i have two array having latitude and longitude of nearby places and also have the user location latiude and longiude now i want to calculate the distance between user location and nearby places and want to show them in listview.

I know that there is a method for calculating distance as

public static void distanceBetween (double startLatitude, double startLongitude, double endLatitude, double endLongitude, float[] results);

Now what is the problem is how to pass these two array having nearby latitude and longitue in this method and get the array of distances.

preguntado el 08 de noviembre de 11 a las 11:11

mira este enlace:… Espero que esto te ayudará. -

thanks for you reply but i want to calculate distance using above method. -

please clarify, technically you have only given us a method signature, which is not enough information to know where the method documentation can be found. Try adding information about the containing class -

Stop using distanceTo because it retourns wrong values:… -

@Karamsa, but in your link it is described that it works right. -

7 Respuestas

Look into distanceTo

Returns the approximate distance in meters between this location and the given location. Distance is defined using the WGS84 ellipsoid.

or distanceBetween

Computes the approximate distance in meters between two locations, and optionally the initial and final bearings of the shortest path between them. Distance and bearing are defined using the WGS84 ellipsoid.

You can create a Location object from a latitude and longitude:

Location locationA = new Location("point A");


Location locationB = new Location("point B");


float distance = locationA.distanceTo(locationB);


private double meterDistanceBetweenPoints(float lat_a, float lng_a, float lat_b, float lng_b) {
    float pk = (float) (180.f/Math.PI);

    float a1 = lat_a / pk;
    float a2 = lng_a / pk;
    float b1 = lat_b / pk;
    float b2 = lng_b / pk;

    double t1 = Math.cos(a1) * Math.cos(a2) * Math.cos(b1) * Math.cos(b2);
    double t2 = Math.cos(a1) * Math.sin(a2) * Math.cos(b1) * Math.sin(b2);
    double t3 = Math.sin(a1) * Math.sin(b1);
    double tt = Math.acos(t1 + t2 + t3);
    return 6366000 * tt;

respondido 29 nov., 20:17

Does this give the distance between two places by road ? - Harsha MV

no it returns Displacement (The Shortest Distance Between Two Points) - Zeeshan Chaudhry

float pk = (float) (180/3.14169); - small misspell, this is not Pi... it should be 3.14159 o Math.PI used (also Math class instead deprecated FloatMath). 57 upvotes and no one noticed? :D - snachmsm

Anyone confirm whether locationA.distanceTo(locationB) takes the altitude into consideration? - Ardilla secreta

What's the second code block for? Why wouldn't you just use Location. distanceBetween()? - spaaarky21

Try This Code. here we have two longitude and latitude values and selected_location.distanceTo(near_locations) function returns the distance between those places in meters.

Location selected_location = new Location("locationA");
Location near_locations = new Location("locationB");
double distance = selected_location.distanceTo(near_locations);

here "distancia" is distance between locationA & locationB (in Meters)

Respondido 17 Feb 21, 19:02

There is only one user Location, so you can iterate List of nearby places can call the distanceTo() function to get the distance, you can store in an array if you like.

Por lo que entiendo, distanceBetween() is for far away places, it's output is a WGS84 ellipsoid.

respondido 08 nov., 11:15

can you please suggest which one provides the exact distance? - Paresh Mayani

    private static Double _MilesToKilometers = 1.609344;
    private static Double _MilesToNautical = 0.8684;

    /// <summary>
    /// Calculates the distance between two points of latitude and longitude.
    /// Great Link -
    /// </summary>
    /// <param name="coordinate1">First coordinate.</param>
    /// <param name="coordinate2">Second coordinate.</param>
    /// <param name="unitsOfLength">Sets the return value unit of length.</param>
    public static Double Distance(Coordinate coordinate1, Coordinate coordinate2, UnitsOfLength unitsOfLength)

        double theta = coordinate1.getLongitude() - coordinate2.getLongitude();
        double distance = Math.sin(ToRadian(coordinate1.getLatitude())) * Math.sin(ToRadian(coordinate2.getLatitude())) +
                       Math.cos(ToRadian(coordinate1.getLatitude())) * Math.cos(ToRadian(coordinate2.getLatitude())) *

        distance = Math.acos(distance);
        distance = ToDegree(distance);
        distance = distance * 60 * 1.1515;

        if (unitsOfLength == UnitsOfLength.Kilometer)
            distance = distance * _MilesToKilometers;
        else if (unitsOfLength == UnitsOfLength.NauticalMiles)
            distance = distance * _MilesToNautical;

        return (distance);


Respondido 11 Oct 13, 18:10

distanceTo will give you the distance in meters between the two given location ej target.distanceTo(destination).

distanceBetween give you the distance also but it will store the distance in a array of float( results[0]). the doc says If results has length 2 or greater, the initial bearing is stored in results[1]. If results has length 3 or greater, the final bearing is stored in results[2]

espero que esto ayude

i've used distanceTo to get the distance from point A to B i think that is the way to go.

Respondido el 05 de Septiembre de 13 a las 18:09

public double distance(Double latitude, Double longitude, double e, double f) {
        double d2r = Math.PI / 180;

        double dlong = (longitude - f) * d2r;
        double dlat = (latitude - e) * d2r;
        double a = Math.pow(Math.sin(dlat / 2.0), 2) + Math.cos(e * d2r)
                * Math.cos(latitude * d2r) * Math.pow(Math.sin(dlong / 2.0), 2)
        double c = 2 * Math.atan2(Math.sqrt(a), Math.sqrt(1 - a));
        double d = 6367 * c;
                return d;


Respondido 19 Abr '16, 20:04

I wanted to implement myself this, i ended up reading the Wikipedia page on Great-circle distance formula, because no code was readable enough for me to use as basis.

Ejemplo de C #

    /// <summary>
    /// Calculates the distance between two locations using the Great Circle Distance algorithm
    /// <see cref=""/>
    /// </summary>
    /// <param name="first"></param>
    /// <param name="second"></param>
    /// <returns></returns>
    private static double DistanceBetween(GeoLocation first, GeoLocation second)
        double longitudeDifferenceInRadians = Math.Abs(ToRadians(first.Longitude) - ToRadians(second.Longitude));

        double centralAngleBetweenLocationsInRadians = Math.Acos(
            Math.Sin(ToRadians(first.Latitude)) * Math.Sin(ToRadians(second.Latitude)) +
            Math.Cos(ToRadians(first.Latitude)) * Math.Cos(ToRadians(second.Latitude)) *

        const double earthRadiusInMeters = 6357 * 1000;

        return earthRadiusInMeters * centralAngleBetweenLocationsInRadians;

    private static double ToRadians(double degrees)
        return degrees * Math.PI / 180;

respondido 04 mar '20, 17:03

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