Cómo obtener un número de contacto específico mediante el identificador de contacto

Here my Contact names are Displayed on List View . By clicking the List I get ContactName y Contact Id. From that I want to fetchPhone number by Using either Contact ID or Contact name,Please Help me.

Aquí está mi código

void ReadContacts(String sort) {
    final Uri uri = ContactsContract.Contacts.CONTENT_URI;
    final String[] projection = new String[] {
            ContactsContract.Contacts._ID,
            ContactsContract.Contacts.DISPLAY_NAME
    };
    //boolean mShowInvisible = false;
    String selection = ContactsContract.Contacts.IN_VISIBLE_GROUP + " = '1'";
    String[] selectionArgs = null;
    final String sortOrder = ContactsContract.Contacts.DISPLAY_NAME + " COLLATE LOCALIZED ASC";

    m_curContacts = managedQuery(uri, projection, selection, selectionArgs, sortOrder);
    String[] fields = new String[] {ContactsContract.Data.DISPLAY_NAME};
    m_slvAdapter = new SimpleCursorAdapter(this, 
                android.R.layout.simple_list_item_1, 
                m_curContacts,
                fields, 
                new int[] {android.R.id.text1});
    m_slvAdapter.setFilterQueryProvider(new FilterQueryProvider() {

        public Cursor runQuery(CharSequence constraint) {
            Log.d(LOG_TAG, "runQuery constraint:"+constraint);
            String selection = ContactsContract.Contacts.IN_VISIBLE_GROUP + " = '1'" +
                    " AND "+ ContactsContract.Contacts.DISPLAY_NAME + " LIKE '%"+constraint+"%'";
            String[] selectionArgs = null;//new String[]{"'1'"};//, };
            Cursor cur = managedQuery(uri, projection, selection, selectionArgs, sortOrder);
            return cur;
        }

   });
   m_lvContacts.setAdapter(m_slvAdapter); 
   //  cur.close();

}



public void onItemClick(AdapterView<?> arg0, View v, int position, long id) {
    ContentResolver cr;
    Cursor cursor = (Cursor) m_lvContacts.getItemAtPosition(position);
    String szDisplayName = cursor.getString(cursor.getColumnIndexOrThrow( ContactsContract.Contacts.DISPLAY_NAME));
    String szId = cursor.getString(cursor.getColumnIndexOrThrow( ContactsContract.Contacts._ID));
    int nId = cursor.getInt(cursor.getColumnIndexOrThrow( ContactsContract.Contacts._ID));
    Log.d(LOG_TAG, "Item click:"+position+" szId:"+szId+" nId:"+nId+" Data:"+szDisplayName);
    Toast.makeText(getBaseContext(), "Item click:"+phoneNumber+" szId:"+szId+" nId:"+nId+" Data:"+szDisplayName, Toast.LENGTH_SHORT).show();

}

preguntado el 10 de marzo de 12 a las 07:03

i used the above link but phoneindex produce o value -

stackoverflow.com/questions/3044545/… try to search on SO.Such questions have already asked and you have to just arrange it -

5 Respuestas

Prueba esta

ArrayList<String> phones = new ArrayList<String>();

Cursor cursor = mContentResolver.query(
        CommonDataKinds.Phone.CONTENT_URI, 
        null, 
        CommonDataKinds.Phone.CONTACT_ID +" = ?", 
        new String[]{id}, null);

while (cursor.moveToNext()) 
{
    phones.add(cursor.getString(cursor.getColumnIndex(CommonDataKinds.Phone.NUMBER)));
} 

cursor.close();
return(phones);

respondido 10 mar '12, 07:03

i dont want list of phone number i need a particular number - user933909

Have u checked? I think It return only one number - Dhaval

Prueba esta

public void getNameUsingContactId(String contactId){

    String cContactIdString = ContactsContract.Contacts._ID;
    Uri cCONTACT_CONTENT_URI = ContactsContract.Contacts.CONTENT_URI;
    String cDisplayNameColumn = ContactsContract.Contacts.DISPLAY_NAME;

    String selection = cContactIdString + " = ? ";
    String[] selectionArgs = new String[]{String.valueOf(contactId)};

    Cursor cursor = mContext.getContentResolver().query(cCONTACT_CONTENT_URI, null, selection, selectionArgs, null);
    if ((cursor != null) && (cursor.getCount() > 0)) {
        cursor.moveToFirst();
        while ((cursor != null) && (cursor.isAfterLast() == false)) {
            if (cursor.getColumnIndex(cContactIdString) >= 0) {
                if (contactId.equals(cursor.getString(cursor.getColumnIndex(cContactIdString)))) {
                    String name = cursor.getString(cursor.getColumnIndex(cDisplayNameColumn));
                     break;
                }
            }
            cursor.moveToNext();
        }
    }
    if (cursor != null)
        cursor.close();  
}   

Respondido 12 Oct 16, 15:10

You'll find the phonenumbers in the data table. Find the corresponding raw contact ids in the rawcontacts table (use contact ID as where criteria), use these raw contact ids to query the data table. The phonenumber will have a certain mime type (away from the docs now) so you can recognize them. Hope this helps!

Tips: copy the contacts2.db database from your emulator/device and use Squirrel (SQLite jdbc driver) to poke around in the contacts database. The db is located under /data/data/ look for contacts in the list).

respondido 10 mar '12, 07:03

Guys I got the Answer:

Please Use this Code if you need:

  Cursor cursor = (Cursor) m_lvContacts.getItemAtPosition(position);
        String szDisplayName = cursor.getString(cursor.getColumnIndexOrThrow( ContactsContract.Contacts.DISPLAY_NAME));
        String szId = cursor.getString(cursor.getColumnIndexOrThrow( ContactsContract.Contacts._ID));
        int nId = cursor.getInt(cursor.getColumnIndexOrThrow( ContactsContract.Contacts._ID));
         long l = Long.parseLong(szId);
        int type=ContactsContract.CommonDataKinds.Phone.TYPE_MOBILE;




 cursor = getContentResolver().query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI,
         null,
         ContactsContract.CommonDataKinds.Phone.CONTACT_ID+"='"+szId+"'",
         null, null);

            int phoneNumberIndex = cursor
                    .getColumnIndexOrThrow(ContactsContract.CommonDataKinds.Phone.NUMBER);

            Log.d(TAG, String.valueOf(cursor.getCount()));

            if (cursor != null) {
                Log.v(TAG, "Cursor Not null");
                try {
                    if (cursor.moveToNext()) {
                        Log.v(TAG, "Moved to first");
                        Log.v(TAG, "Cursor Moved to first and checking");
                        phoneNumber = cursor.getString(phoneNumberIndex);
                        System.out.println("HAGSd"+phoneNumber);
                    }
                } finally {
                    Log.v(TAG, "In finally");
                    cursor.close();
                }

respondido 11 mar '12, 10:03

public static final String contactIdByPhoneNumber(Context ctx, String phoneNumber) {
    String contactId = null;
    if (phoneNumber != null && phoneNumber.length() > 0) {
        ContentResolver contentResolver = ctx.getContentResolver();

        Uri uri = Uri.withAppendedPath(ContactsContract.PhoneLookup.CONTENT_FILTER_URI, Uri.encode(phoneNumber));

        String[] projection = new String[] { PhoneLookup._ID };

        Cursor cursor = contentResolver.query(uri, projection, null, null, null);

        if (cursor != null) {
            while (cursor.moveToNext()) {
                contactId = cursor.getString(cursor.getColumnIndexOrThrow(PhoneLookup._ID));
            }
            cursor.close();
        }
    }
    return contactId;
}

Respondido el 02 de junio de 16 a las 11:06

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