Filtrado de elementos de una Lista
Frecuentes
Visto 522 veces
1
Say you want to filter elements out of a List. Running this code triggers something like a concurrency exception as the list is being modified during the loop:
List<String> aList = new ArrayList<String>();
// Add instances to list here ...
for( String s : aList ){
if( "apple".equals( s ) ){ // Criteria
aList.remove(s);
}
}
What is the conventional way of doing this and what other approaches do you know of?
3 Respuestas
3
best way is to use iterator.remove()
contestado el 02 de mayo de 12 a las 19:05
1
For your case, you can simply use a solution without any iteration manually done (removeAll takes care about this):
aList.removeAll("apple");
It removes all "apple" elements from the list.
contestado el 02 de mayo de 12 a las 19:05
1
Agree with the above two if you're iterating or have a collection of simple elements. If your condition or objects are more involved, consider Apache Commons CollectionUtils' filter method, which allows you to define a predicate encapsulating your condition and which is then applied to each element of the collection. Given your collection aList and a predicate applePredicate, the method of invocation would then be:
org.apache.commons.collections.CollectionUtils.filter(aList, applePredicate);
http://commons.apache.org/collections/apidocs/org/apache/commons/collections/CollectionUtils.html#filter(java.util.Collection, org.apache.commons.colecciones.Predicado)
contestado el 02 de mayo de 12 a las 19:05
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posible duplicado de Llamar a eliminar en el bucle foreach en Java - assylias