¿Resultados de orden SQL y luego extraer más de una columna?
Frecuentes
Visto 98 veces
-1
I am writing a SQL function. I would like to order all of the data from a table (any table, doesnt matter for this question). I would then like to order the data on one column. Then once this order has been performed I would like to extract a few of the columns from the top row (after the ordering).
I dont think I can use partititon by because the ordering is on the whole data, not groups of it?
Im stuck because you can only use ORDER BY at the end of a function
2 Respuestas
1
Sounds like a complicated description of a SELECT TOP 1
consulta:
SELECT TOP 1 t.ColumnA, t.ColumnD, t.ColumnF
FROM YourTable t
ORDER BY t.ColumnB DESC,
Would order the table by ColumnB
in descending order, then return Columns A
, D
and F
.
I'm not sure you even need a function.
Respondido el 12 de junio de 12 a las 13:06
0
Intente algo como esto:
CREATE FUNCTION fn_dummy()
RETURNS TABLE
AS
RETURN (
SELECT TOP 1
name, object_id, type_desc
FROM sys.tables
ORDER BY create_date DESC)
Respondido el 12 de junio de 12 a las 13:06
No es la respuesta que estás buscando? Examinar otras preguntas etiquetadas sql sql-server sql-server-2008 or haz tu propia pregunta.
What are you trying to do exactly? Is it a table valued funtion? - Mithrandir
select top (n) * from any_table order by anything - Nikola Markovinović