Cálculo de diferencias de elementos posteriores de una secuencia en F#
Frecuentes
Visto 276 veces
4
I have a sequence of floats in F#, and I need to get a sequence defined of (Math.Log currentElement)/(Math.Log previousElement)
. Obviously it will be shorter than the original sequence by one element.
What is the most elegant way to achieve this in F#? I was thinking to use a seq{} expression with a for loop inside, but even then handling the first element in a reasonably nice way seems difficult...
2 Respuestas
9
items |> Seq.pairwise |> Seq.map (fun (x, y) -> log y / log x)
Respondido 28 ago 12, 15:08
0
O si lo prefieres:
let f (x, y) = (log y) / (log x)
let ans = s |> Seq.pairwise |> Seq.map f
Respondido 28 ago 12, 22:08
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