# Timedelta se multiplica con float en python

I have two dates and can calculate timedelta as usual.

But I want to calculate some percent with resulting timedelta:

full_time = (100/percentage) * timdelta

But it seems that it can only multiplying with interegs.

Como puedo usar float en lugar de int as multiplier?

Ejemplo:

percentage     = 43.27
passed_time    = fromtimestamp(fileinfo.st_mtime) - fromtimestamp(fileinfo.st_ctime)
multiplier     = 100 / percentage   # 2.3110700254217702796394730760342
full_time      = multiplier * passed_time # BUG: here comes exception
estimated_time = full_time - passed_time

If is used int(multiplier) — accuracy suffers.

preguntado el 05 de septiembre de 12 a las 10:09

You're right, timedelta just supports multiplication or division with intergers, but why you don't perform the math operations in sequence step by step? full_time = passed_time * 100 / int(percentage) -

@Colin O'Coal, because of accuracy: 2 != 2.3131. Comparar: 571 * 2 = 1142 (19,03(3) minutes); 571 * 2.3131 = 1320,7801 (22,0130016(6) minutes). Difference is about 3 minutos (!)-

## 2 Respuestas

You can convert to total seconds and back again:

full_time = timedelta(seconds=multiplier * passed_time.total_seconds())

timedelta.total_seconds is available from Python 2.7; on earlier versions use

def timedelta_total_seconds(td):
return (td.microseconds + (td.seconds + td.days * 24 * 3600) * 10**6) / float(10**6)

Respondido el 05 de Septiembre de 12 a las 10:09

just thank you! Honestly I forgot about timedelta constructor. And thank you for "back compatibility" ) - Крайст

Podrías usar total_seconds():

datetime.timedelta(seconds=datetime.timedelta(minutes=42).total_seconds() * 0.8)
# => datetime.timedelta(0, 2016)

Respondido el 05 de Septiembre de 12 a las 10:09

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