Pasar el parámetro Integer de Vb6 a C++ dll

Public Declare Function getTable Lib "LuxDll.dll" (ByVal table As Integer, _
     ByVal col As Integer) As String

BSTR _stdcall getTable(int table, int col)

Dim i
i=5
debug.print getTable(i, 1)

Lo anterior funciona

but if I did "Dim i as integer" it crashes

should the parameters in VB be something other than integer?

Muchas Gracias

EDIT: I should specify the C++ side crashes and its because the integer value gets passed as -65000ish

preguntado el 27 de noviembre de 13 a las 00:11

haha, I should have tried this before asking.. that worked :D thanks.. also thanks for the edit (I always butch the formatting lol). Should I change the byval table as integer and col as integer to longs too? it seems to work with them as integers but I dont understand why -

2 Respuestas

In mixing VB6 with C/++, a C int equates to a Long in VB6: so Dim i As Long should work. That is no longer true in .NET. And though you had it right, it should be BYVAL (another common mistake)

respondido 27 nov., 13:00

When I do something like this, I try to be very explicit with my types. Int changes from implementation to implementation, platform to platform.

Utilice la herramienta signed long, or the equivalent type in VB Int32 everywhere, instead of int or integer. That will save you lots of pain.

There's also something to be said for being explicit about your types for documentation purposes. I have had tons of problems trying to get a DLL from a vendor with bad documentation working. Something as simple as saying Int64, or unsigned short will go a long way to informing someone trying to interface with your DLL how it is to be dealt with.

respondido 27 nov., 13:00

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