Reemplace la última aparición de palabra entre 2 palabras con RegEx
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I'm working with RegEx on Java and here is where I stuck.
I have a simple string like
String sample1 = "word 231 sadas aslkjasf anything ORDER what whut ASC hello ORDER whatever."
I have to find every substring until the last occurrence of ASC
entre dos ORDER
s and replace them with word QQQ
.
He aquí algunos ejemplos:
String sample1 = "word 231 sadas aslkjasf anything ORDER what whut ASC hello ORDER whatever.";
String result1 = "word 231 sadas aslkjasf anything QQQ hello ORDER whatever.";
// replaced "ORDER what whut ASC"
String sample2 = "word 111 sadas anything ORDER what whut yeap ASC nope ASC maybe ORDER yeah.";
String result2 = "word 111 sadas anything QQQ maybe ORDER yeah.";
// replaced "ORDER what whut yeap ASC nope ASC"
1 Respuestas
1
prueba este
s = s.replaceAll("(ORDER.*ASC)(?=.*?ORDER.*)", "QQQ");
contestado el 28 de mayo de 14 a las 12:05
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what to do for remove last "ORDER" too? - user2761286
@user2761286 State clearly in question what is the intended result. Currently you have ORDER in the output. - Ulugbek Umírov
what if i want to remove that ORDER too? - user2761286
s.replaceAll("(ORDER.*ORDER)", "QQQ"); will replace ORDER...ORDER with QQQ - Evgeniy Dorofeev