cómo pasar el valor <entrada> a php usando carga ajax
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I am trying to pass a value of an input item to php when loading the php file using ajax_load. this is that I have so far but it's not working.
html and jquery:
<tr>
<td></td>
<td>
<button class="grey">Test Settings</button></td>
</tr>
<tr>
<td></td>
<td><div class="font-size-15 color-semi-black" id="result"></div></td>
</tr>
<input type="hidden" name="control" value="1"/>
<!--Test Settings-->
{literal}
<script>
$.ajaxSetup({
cache: false
});
var ajax_load = "<img src='images/loaders/small-loader.gif' alt='loading...' />";
var value = $("input[name='control']").val();
// load() functions
var loadUrl = "demo/test_settings.php?val=" + value;
$("button").click(function() {
$("#result").html(ajax_load).load(loadUrl);
});
</script>
{/literal}
php
if ($val == '1'){
//process code here.
}
It's not passing the value of the input. any suggestions?
3 Respuestas
2
your request is going with GET
como esto:-
/demo/test_settings.php?val=1&_=1401278450924
so you need to get your values by $_GET
on test_settings.php
como
if ($_GET['val'] == '1'){
contestado el 28 de mayo de 14 a las 13:05
thank you for your suggestion. had a few problem with ?val=1&_=1401278450924 but I changed to .php?val=1"; and that works - user3620142
1
En su $.load
pass data to it as a parameter.
$("button").click(function(){
$("#result").html(ajax_load).load(loadUrl , {
val : ...
});
});
En su archivo php:
if (isset($_REQUEST["val"]) && $_REQUEST["val"] == 1) {
...
}
If you pass an object, it is passed as POST, otherwise it is passed as GET.
contestado el 28 de mayo de 14 a las 13:05
Y, qué piensas load()
¿lo hace? - aspirina
Edited it. Somehow forgot you can actually pass parameters to load, my bad. - Mareckmareck
This is not the problem, he is already passing the value in the query string. The problem is how he retrieves it in php - Steve
Yeah, but passing the values like that is a better way to deal with it. - Mareckmareck
guys, I was able to use suggestions from here and do this. test_connection.php?val=1"; php: ($_GET['val'] == '1'){ and it works fine - user3620142
0
if (count($_GET) && $_GET['val'] == '1'){
}
contestado el 28 de mayo de 14 a las 13:05
No es la respuesta que estás buscando? Examinar otras preguntas etiquetadas php ajax or haz tu propia pregunta.
No need to. He can capture it trough query string - asprin
there are numbers of ajax jquery tutorials. try to search in Google - user3470953
it would be very helpful if you could just post the actual content of your test_settings.php file too. Otherwise, we assume that your $val is set as: $val = $_GET['val']. - Vincent Edward Gedaria Binua
thank you all for commenting. the reason I did not post the content of the php is because it is about 200 lines of coding which is not related to this. but same suggestion as below works great. - user3620142